Category: Programming

COVID-19 has changed the world in a sustainable way. Suddenly, even the most conservative bosses realized that it is perfectly efficient to allow developers to work from home. Remote work may easily be one of the most transformative trends in the 21st century: It will have an impact on almost every conventional job under the sun—and the year-over-year double-digit growth of freelancing platforms such as Upwork and Fiverr proves this point.

This article helps you to identify the best places to look for work-from-home, remote freelancing jobs—with a focus on jobs or gigs in the attractive programming sector. The average freelancer earns $51-$61 per hour and, thus, it may be an attractive way for you to build a second income stream besides your main job income.

So, without any further introduction, let’s dive into the top places to look for freelancing gigs! Here’s a quick overview of all gigs—ordered by relevance for freelance developers:

1. TopTal Developers
2. StackOverflow Jobs
3. Hacker News Jobs
4. GitHub Jobs
5. Finxter Freelancer
6. PeoplePerHour Developer Jobs
7. Authentic Jobs
8. Vue Jobs
9. Remote Leads
10. Redditors For Hire
11. WeWorkRemotely
12. Upwork
13. Fiverr
14. Twitter Company Remote Jobs

ALL LINKS OPEN IN A NEW TAB!

1. TopTal Developers

2. StackOverflow Jobs

3. Hacker News Jobs

4. GitHub Jobs

5. Finxter Freelancer

6. PeoplePerHour Developer Jobs

7. Authentic Jobs

8. Vue Jobs

9. Remote Leads

10. Redditors For Hire

11. WeWorkRemotely

12. Upwork

13. Fiverr

14. Twitter Company Remote Jobs

What Are The Best Freelancing Sites for Coders? Video Lesson

Want to become a freelance developer earning six-figures? Check out the FINXTER Python freelancer course—the world’s most in-depth Python freelancer program!

The post Top 14 Places to Find Remote Freelance Developer Gigs and Work From Home first appeared on Finxter.

Summary: The slice notation list[::-1] with default start and stop indices and negative step size -1 reverses a given list.

Problem: Given a list of elements. How to reverse the order of the elements in the list.

Example: Say, you’ve got the following list:

['Alice', 'Bob', 'Carl', 'Dora']

Your goal is to reverse the elements to obtain the following result:

['Dora', 'Carl', 'Bob', 'Alice']

Slicing with Default Start and Stop Values

Slicing is a concept to carve out a substring from a given string.

Use slicing notation s[start:stop:step] to access every step-th element starting from index start (included) and ending in index stop (excluded).

All three arguments are optional, so you can skip them to use the default values (start=0, stop=len(lst), step=1). For example, the expression s[2:4] from string 'hello' carves out the slice 'll' and the expression s[:3:2] carves out the slice 'hl'. Note that slicing works the same for lists and strings.

You can use a negative step size (e.g., -1) to slice from the right to the left in inverse order. Here’s how you can use this to reverse a list in Python:

# Reverse a List with Slicing
names = ['Alice', 'Bob', 'Carl', 'Dora']
names = names[::-1]
print(names)
# ['Dora', 'Carl', 'Bob', 'Alice']

Python masters know slicing from the inside out. Do you want to improve your slicing skills? Check out my book “Coffee Break Python Slicing” that will make you a slice pro in no time!

Alternatives Reversing List

Alternatively, you can also use other methods to reverse a list.

• list.reverse() — Best if you want to reverse the elements of list in place.
• list[::-1] — Best if you want to write concise code to return a new list with reversed elements.
• reversed(list) — Best if you want to iterate over all elements of a list in reversed order without changing the original list.

The method list.reverse() can be 37% faster than reversed(list) because no new object has to be created.

Try it yourself in our interactive Python shell:

Exercise: Run the code. Do all methods result in the same reversed list?

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

Join the free webinar now!

The post Python Reverse List with Slicing — An Illustrated Guide first appeared on Finxter.

To remove duplicates from a Python list while preserving the order of the elements, use the code list(dict.fromkeys(list)) that goes through two phases: (1) Convert the list to a dict using the dict.fromkeys() function with the list elements as keys and None as dict values. (2) Convert the dictionary back to a list using the list() constructor. As dictionaries preserve the order of the keys, the list ordering is preserved.

Problem: How to remove duplicates from a Python list while keeping the order of the list elements preserved?

You may find this question a little awkward. What has removing duplicates to do with preserving the order of the elements? The reason is simple: a well-known and efficient way to remove duplicates from a list is to convert the list to a set—which is duplicated-free—and converting it back to a list. Here’s what you may find everywhere:

lst = [42, 42, 'Alice', 'Alice', 1]
dup_free = list(set(lst))
print(dup_free)
# ['Alice', 42, 1]

The back-and-forth conversion list(set(lst)) removes all duplicates from the list. However, it doesn’t preserve the order of the elements. In the example, the string 'Alice' now appears before the integer 42.

So, how to remove duplicates while preserving the order of the elements?

The most Pythonic and blazingly fast approach is to use a dictionary:

lst = [3, 3, 22, 22, 1]
result = list(dict.fromkeys(lst))
print(result)
# [3, 22, 1]

The dict.fromkeys() method creates a new dictionary using the elements from an iterable as the keys. Python dictionary keys are unique by default so converting our list into a dictionary will remove duplicates automatically. Once this has been done with our initial list, converting the dictionary back results in the duplicate-free list.

This is the most Pythonic way to remove duplicates from a Python list while preserving the order.

Is this method fast? Like sets, dictionaries use hash tables, which means they are extremely fast.

Do you want to develop the skills of a well-rounded Python professional—while getting paid in the process? Become a Python freelancer and order your book Leaving the Rat Race with Python on Amazon (Kindle/Print)!

Do Python Dictionaries Preserve the Ordering of the Keys?

Surprisingly, the dictionary keys in Python preserve the order of the elements. So, yes, the order of the elements is preserved. (source)

Countless online resources like this argue that the order of dictionary keys is not preserved. They assume that the underlying implementation of the dictionary key iterables uses sets—and sets are well-known to be agnostic to the ordering of elements. But this assumption is wrong. The built-in Python dictionary implementation in cPython preserves the order.

Here’s another example:

lst = ['Alice', 'Bob', 'Bob', 1, 1, 1, 2, 3, 3]
dic = dict.fromkeys(lst)
print(dic)
# {'Alice': None, 'Bob': None, 1: None, 2: None, 3: None}

You see that the order of elements is preserved so when converting it back, the original ordering of the list elements is still preserved:

print(list(dic))
# ['Alice', 'Bob', 1, 2, 3]

However, you cannot rely on it because any Python implementation could, theoretically, decide not to preserve the order (notice the “COULD” here is 100% theoretical and does not apply to the default cPython implementation).

If you need to be certain that the order is preserved, you can use the ordered dictionary library. In cPython, this is just a wrapper for the default dict implementation.

Source Article: How to Remove Duplicates From a Python List?

Removing Duplicates From Ordered Lists For Older Versions

Dictionaries only became ordered in all Python implementations when Python 3.7 was released (this was also an implementation detail of CPython 3.6). 

So, if you’re using an older version of Python, you will need to import the OrderedDict class from the collections package in the standard library instead:

 from collections import OrderedDict lst = [1, 1, 9, 1, 9, 6, 9, 7] result = list(OrderedDict.fromkeys(lst))

The output is the following duplicate-free list with the order of the elements preserved:

 print(result) # [1, 9, 6, 7]

Interactive Code Shell

Let’s try this method in our interactive Python shell:

Exercise: Run the code. Does it work?

You can find more ways to remove duplicates while preserving the order in this detailed blog article:

Related tutorial: Python List: Remove Duplicates and Keep the Order

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

Join the free webinar now!

The post How to Remove Duplicates From a Python List While Preserving Order? first appeared on Finxter.

What is the net worth of a freelance developer? In this article, you’ll learn the expected net worth of a freelance developer as a rough estimate.

Definition net worth: Net worth is the value the assets a person or corporation owns, minus the liabilities they owe. It is an important metric to gauge a company’s health and it provides a snapshot of the firm’s current financial position. (source)

The net worth of a freelance developer who earns the average $134,400 per year and saves 10% per year in a low-cost S&P500 index fund is $204,192 after 10 years, $687,592 after 20 years, and $4,541,140 after 40 years. Under these assumptions, a freelance developer with a savings rate of 20% reaches $1,000,000 net worth in year 18. An alternative measurement stick is a simple P/E valuation based on which the expected net worth of a freelance developer would be approximately 10x earnings which is $1,344,000.

Let’s see how we developed these numbers based on realistic assumptions and averaged statistics over millions of US workers.

To come up with a meaningful figure, we’re going for a few assumptions:

Assumptions

• We assume a US-based freelance developer. Most non-US freelancers can approximate the net worth and earning potential of a US-based freelance developer by using freelancing platforms such as Upwork and Fiverr to participate in the US economy.
• We assume that the freelance developer has average skills earning the average hourly rate of a Python developer of $56 per hour. The average Python developer worldwide earns $56 per hour (fluctuations between $51 and $61). This statistic is based on five credible online sources including the US government. You can learn more about the hourly rate here.
• Based on a conservative estimation, your income as a Python freelancer will be $134,400 per year assuming a normal workday of eight billed hours per day for 300 days per year.
• We assume that the freelancer has a saving rates of 10%. The average savings rate in the US has been between 7% and 17% during the COVID-19 crisis:

• We further assume that the saved money is invested in a low-cost index fund generating the 100-y historic return of 9% after fees. (source)

Calculation Net Worth Freelance Developer

Let’s see how the net worth of a freelancer would progress over a period of 50 years based on these assumptions.

So, if you start with age 20, you’d have an $11,000,000 net worth at age 70—quite a legacy! Here’s the yearly table:

After only 24 years working as a freelance developer, you’ll become a millionaire! Note that this graphic doesn’t talk about inflation which could reduce your pace by 2-3% per year. On the other hand, inflation will probably also cause your yearly earnings to rise. Also, you could probably increase your savings rate as you earn more and more through investments. Together, these two factors may balance out.

The same discussion must be made about the development of your skills. In this simulation, we assume that your skills remain average all your life. In my experience, you can reach this average skill relatively quickly after 4-5 years focused effort. You can check out my detailed Python freelancer program to learn how you can accelerate the process towards your thriving freelance developing business online. So, your earnings will probably grow over the years which makes it easier and easier to save more and more money over time.

Related video:

Note that with 20% savings rate (which is possible for most people), you’d reach your goals much earlier:

With a savings rate of 20%, you can reach the $10 million mark already after 40 years and the $1 million mark after 18 years.

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

Join the free webinar now!

The post Freelance Developer Net Worth first appeared on Finxter.

Problem: Given a list. How to access the last element of this list?

Example: You have the list ['Alice', 'Bob', 'Liz'] and you want to get the last element 'Liz'.

Quick solution: Use negative indexing -1.

friends = ['Alice', 'Bob', 'Liz']
print(friends[-1])
# Liz

To access the last element of a Python list, use the indexing notation list[-1] with negative index -1 which points to the last list element. To access the second-, third-, and fourth-last elements, use the indices -2, -3, and -4. To access the n last elements of a list, use slicing list[:-n-1:-1] with negative stop index -n and negative step size -1.

Method 1: Access the Last Element with Negative Indexing -1

To bring everybody on the same page, let me quickly explain indices in Python by example. Suppose, you have list ['u', 'n', 'i', 'v', 'e', 'r', 's', 'e']. The indices are simply the positions of the characters of this string.

Positive Index: The first character has index 0, the second character has index 1, and the i-th character has index i-1.

Negative Index: The last character has index -1, the second last character has index -2, and the i-th last character has index -i.

Now, you can understand how to access the last element of the list:

friends = ['Alice', 'Bob', 'Liz']
print(friends[-1])
# Liz

But how to access the second-last element? Just use index -2!

friends = ['Alice', 'Bob', 'Liz']
print(friends[-2])
# Bob

Method 2: Access the n Last Elements with Slicing

But what if you want to access the n last elements? The answer is slicing.

The default slicing operation list[start:stop:step] accesses all elements between start (included) and stop (excluded) indices, using the given step size over the list. For example, the slicing operation friends[0:3:2] would start with the first element 'Alice' and end with the third element 'Liz' (included), but taking only every second element due to the step size of 2—effectively skipping the second element 'Bob'.

You can use slicing with negative start and stop indices and with negative stop size to slice from the right to the left. To access the n last elements in the slice, you’d therefore use the following code:

universe = ['u', 'n', 'i', 'v', 'e', 'r', 's', 'e'] # Access the n=4 last element from the list:
n = 4
print(universe[:-n-1:-1])
# ['e', 's', 'r', 'e']

There are different points to consider in the code:

• You use a negative step size -1 which means that you slice from the right to the left.
• If you don’t provide a value for start, stop, or step indices, Python takes the default ones. For example, we don’t provide the start index and perform negative slicing so Python starts from the last element 'e'.
• You want to get the n last elements. The n-th last element has index -n. But as the stop index is never included in the slice, we need to slice one step further to the left—to the element with index -n-1 to include the element with index -n.

Try this yourself in our interactive code shell:

Exercise: What happens if the list has less than n characters?

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

Join the free webinar now!

The post How to Get the Last Element of a Python List? first appeared on Finxter.

Summary: To update a key in a dictionary if it doesn’t exist, you can check if it is present in the dictionary using the in keyword along with the if statement and then update the key-value pair using subscript notation or update() method or the * operator. Another workaround for this is, using the setdefault(key[, default]) method which updates the dictionary with the key-value pair only if it doesn’t exist in the dictionary otherwise, it returns the pre-existing items.

Problem: Given a dictionary; how to update a key in it if the key does not exist?

Example:

device = { "brand": "Apple", "model": "iPhone 11",
} < Some Method to Check if key-value pairs "color" : "red" and "year" : 2019 exists or not and then update/insert it in the dictionary > print(device)

Output:

{'brand': 'Apple', 'model': 'iPhone 11', 'color': 'red', 'year': 2019}

To solve our problem statement, let us follow a modular approach and break down our discussion in this article into three parts.

1. In the first section let us discuss the methods to update or insert a key,
2. In the second section, we shall be discussing the methods to check if the key is present in the dictionary,
3. Finally, we shall merge our concepts to reach the final solution.

Without further delay let us dive into the solutions right away.

Section 1: Insert/Update A Key In A Dictionary

Method 1: Create A New Key-Value Pair Assign It To Dictionary | Subscript Notation

We can create a new index key and then assign a value to it and then assign the key-value pair to the dictionary. Let us have a look at the following program which explains the syntax to create a new key-value pair and assign it to the dictionary:

device = { "brand": "Apple", "model": "iPhone 11",
} device["year"] = 2019
print(device)

Output:

{‘brand’: ‘Apple’, ‘year’: 2019, ‘model’: ‘iPhone 11’}

Method 2: Use The update() Function

The update() method is used to insert or update a specific key-value pair in a dictionary. The item to be inserted can also be another iterable. Also, if the specified key is already present in the dictionary then the previous value will be overwritten.

The following code demonstrates the usage of the update() method:

device = { "brand": "Apple", "model": "iPhone 11",
} device.update({"year" : 2019})
print(device)

Output:

{'brand': 'Apple', 'model': 'iPhone 11', 'year': 2019}

Method 3: Using The * Operator

We can combine an existing dictionary and a key-value pair using the * operator. Let us have a look at the following code to understand the concept and usage of the * operator to insert items in a dictionary.

device = { "brand": "Apple", "model": "iPhone 11",
}
device = {**device,**{"year":2019}}
print(device)

Output:

{'brand': 'Apple', 'model': 'iPhone 11', 'year': 2019}

Disclaimer: In the above methods if we do not check the presence of a key in the dictionary, then the value will be overwritten in the dictionary if the key and value are already existing in the dictionary. Now, that brings us to the second section of our discussion!

Section 2: Check If A Key Is Present In A Dictionary

Method 1: Using The in Keyword

The in keyword is used to check if a key is already present in the dictionary. The following program explains how we can use the in keyword.

device = { "brand": "Apple", "model": "iPhone 11", "year":2018
} if "year" in device: print("key year is present!")
else: print("key year is not Present!") if "color" in device: print("key color is present!")
else: print("key color is not present!") 

Output:

key year is present!
key color is not present!

Note: Just like the in keyword, we can use the not in keyword to check if the key is not present in the dictionary.

Method 2: Using keys() Function

keys() is an inbuilt method that extracts the keys present in a dictionary and stores them in a list. Thus with the help of this inbuilt method, we can determine if a key is present in the dictionary.

Let us have a look a the following program to understand how to use the keys() method and check the availability of a key in the dictionary:

device = { "brand": "Apple", "model": "iPhone 11", "year":2018
} if "year" in device.keys(): print("key year is present!")
else: print("key year is not Present!") if "color" in device.keys(): print("key color is present!")
else: print("key color is not present!") 

Output:

key year is present!
key color is not present!

Method 3: Using has_key() Function

If you are using Python 2.x then you might fancy your chances with the has_key() method which is an inbuilt method in Python that returns true if the specified key is present in the dictionary else it returns false.

Caution: has_key() has been removed from Python 3 and also lags behind the in keyword while checking for the presence of keys in a dictionary in terms of performance. So you must use avoid using it if you are using Python 3 or above.

Now let us have a look at the following program to understand how we can use the has_key() method:

device = { "brand": "Apple", "model": "iPhone 11", "year":2018
} if device.has_key("year"): print("key year is present!")
else: print("key year is not Present!") if device.has_key("color"): print("key color is present!")
else: print("key color is not present!") 

Output:

key year is present!
key color is not present!

Phew!!! Now, we are finally equipped with all the procedures to check as well as update a key in a dictionary if it does not exist in the dictionary. That brings us to the final stages of our discussion where we shall combine our knowledge from section 1 and section 2 to reach the desired output.

Update Key In Dictionary If It Doesn’t Exist

Solution 1: Using Concepts Discussed In Section 1 and Section 2

Since we are through with the concepts, let us dive into the program to implement them and get the final output:

device = { "brand": "Apple", "model": "iPhone 11",
} # Method 1 : Create a New Key_Value pair and check using the in keyword
if "color" not in device: device["color"] = "red" # Method 2 : Use update() method and check using the not in keyword
if "year" not in device.keys(): device.update({"year" : 2019}) # Method 2 : Use * operator and check using the not in keyword
if "brand" not in device.keys(): device.update({"brand" : "Samsung" })
else: print(device)

Output:

{'brand': 'Apple', 'model': 'iPhone 11', 'color': 'red', 'year': 2019}

Solution 2: Using setdefault() Method

setdefault() is an inbuilt Python method which returns the value of a key if it already exists in the dictionary and if it does not exist then the key value pair gets inserted into the dictionary.

Let us have a look at the following program which explains the setdefault() method in python:

device = { "brand": "Apple", "model": "iPhone 11", "color": "red"
} device.setdefault('year',2019)
print(device)

Output:

{'brand': 'Apple', 'model': 'iPhone 11', 'color': 'red', 'year': 2019}

Conclusion

I hope after reading this article you can check and update values in a dictionary with ease. In case you have any doubts regarding Python dictionaries, I highly recommend you to go through our tutorial on Python dictionaries.

Please subscribe and stay tuned for more interesting articles!

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

Join the free webinar now!

The post How To Update A Key In A Dictionary In Python If The Key Doesn’t Exist? first appeared on Finxter.

Problem: If you assign a list object to a new variable using new_list = old_list, any modification to new_list changes old_list. What’s the reason for this and how can you clone or copy the list to prevent this problem?

Example: Let’s consider the following example.

old_list = ['Alice', 'Bob', 'Carl']
new_list = old_list
new_list.append(42)
print(old_list)
# ['Alice', 'Bob', 'Carl', 42]

Appending an element to the new_list also modifies the original list old_list. Thus, old_list has now four elements—even though you didn’t change it directly.

Explanation

This problem of simultaneously modifying “two” lists arises because you don’t have two lists but only a single one.

In Python, everything is an object. You create a new list object ['Alice', 'Bob', 'Carl'] that resides in your machine’s memory. Both variable names new_list and old_list point to the same object in memory—if you modify one, you also modify the other!

The following interactive tool visualizes the memory used by the Python interpreter when executing this particular code snippet:

Exercise: Visualize how the problem arises by clicking “Next”.

Do you understand the source of the problem? Great, let’s dive into the solutions starting with a short overview!

Solution Overview

You can see all three solutions discussed in this tutorial in our interactive Python shell:

Exercise: Change the original list. Do all three methods still produce the same output?

Next, you’ll learn about each method in greater detail!

Method 1: Slicing

The easiest way to create a shallow copy of a Python list is via slicing:

# Method 1: Slicing
old_list = ['Alice', 'Bob', 'Carl']
new_list = old_list[:]
new_list.append(42)
print(new_list)
# ['Alice', 'Bob', 'Carl']

The slicing operation old_list[:] creates a new list, so the variables new_list and old_list now point to different objects in memory. If you change one, the other doesn’t change.

This is the way with the least amount of characters and many Python coders would consider this the most Pythonic one. If you want to learn more about slicing, watch the following video and dive into the detailed blog tutorial.

Related Tutorial: Introduction to Slicing in Python

Method 2: Copy

An alternative is to use the list.copy() method that creates a shallow copy of the list.

# Method 2: Copy
old_list = ['Alice', 'Bob', 'Carl']
new_list = old_list.copy()
new_list.append(42)
print(old_list)
# ['Alice', 'Bob', 'Carl']

The list.copy() method copies all list elements into a new list. The new list is the return value of the method. It’s a shallow copy—you copy only the object references to the list elements and not the objects themselves.

The result is the same as the slicing method: you have two variables pointing to two different list objects in memory.

You can learn more about the list.copy() method in my detailed blog tutorial and the following video:

Related Tutorial: Python list.copy() [Ultimate Guide]

Method 3: List Comprehension

A third way to solve the problem of two lists pointing to the same object in memory is the list comprehension way to create new lists.

# Method 3: List Comprehension
old_list = ['Alice', 'Bob', 'Carl']
new_list = [x for x in old_list]
new_list.append(42)
print(old_list)
# ['Alice', 'Bob', 'Carl']

List comprehension is a compact way of creating lists. The simple formula is [expression + context].

• Expression: What to do with each list element?
• Context: What elements to select? The context consists of an arbitrary number of for and if statements.

You can watch the tutorial video and read over the related blog article to learn more about it!

Related Tutorial: An Introduction to List Comprehension

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

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The post List Changes After Assignment — How to Clone or Copy It? first appeared on Finxter.

Summary: Use one of the following methods to format strings that contain curly braces:

• Use double curly braces {{}}
• Use the old string formatting, i.e. the % operator
• Use the JSON Library
• Use Template Strings

Problem: Given a string literal with curly braces; how to format the string and ensure that the curly braces are available in the output?

To understand the problem statement, let us have a look at the following example:

Example:

x = "{Serial No.}{0} ".format(1)
print(x)

Output:

Traceback (most recent call last): File "main.py", line 1, in <module> x = "{Serial No.}{0} ".format(1)
KeyError: 'Serial No'

From the above example it is clear that when we execute a print statement with a literal text that contains the curly braces, the program raises a KeyError unless we provide the proper syntax for string formatting. In this article, we shall be discussing the methods to overcome this problem and print our text with the curly braces along with string formatting. Therefore:

Desired Output:

{Serial No:}1

Before we dive into the solutions, let us have a look at the reason behind the KeyError exception.

KeyError Exception

A KeyError is raised when you try to access or look for a value in a dictionary that does not exist. For example, consider the following dictionary:

profile={ 'Name':'Shubham', 'id':12345
}
print(profile['age'])

The above code will raise a KeyError exception. This is because we are trying to access the key ‘age‘ which does not exist within the dictionary profile. Since the key does not exist, we cannot access any value using this key.

Here’s what we get when we execute the above program:

Traceback (most recent call last): File "main.py", line 8, in <module> print(profile['age'])
KeyError: 'age'

No, the question that needs to be addressed is – “Why are we getting the KeyEror while formatting a string that contains a text along with curly braces?”

Reason: The .format() generally expects things inside { } to be keys but in this case, it is unable to do so since ‘Serial No.' is not a key. Therefore .format() unable to parse the data. This results in a KeyError as we are trying to access a key-value that does not exist.

Now that we know why we are getting the KeyError let us dive into the solutions to avoid this error.

Method 1: Using Double Curly Braces

We already discussed that {} inside a format string are special characters, therefore if we want to include braces as a part of our literal text, we need to tell the .format string parser that the given curly braces must be escaped and considered as a part of the given text literal. This can be easily done by doubling the curly braces encompassing the string, that is using the following syntax: {{Serial No.}}

The following program denotes how we can use double curly braces to reach our solution:

x = "{{Serial No.}}{0} ".format(1)
print(x)

Output:

{Serial No.}1 

Method 2: Using The Old String Formatting Style (%)

If you do not want to use the double curly braces then you might fancy the old style of string formatting that uses the modulo (%) operator. Let us have a look at the following program to understand how we can use the modulo operator to print our string along with curly braces in it.

x = " {Serial No.}%s"
print (x%(1)) 

Output

{Serial No.}1

Method 3: Using The JSON Library

In situations where you need to deal with complex JSON strings, the most efficient method of dealing with such scenarios is to use the JSON library in your program.

★ The json.dumps() method is used to covert a Python object, like a dictionary, to a JSON string.

Consider the following example which explains how we can use the JSON library to print JSON strings:

import json group = "Admin"
id = 1111
x = {"ID" : id, "Group" : group}
print(json.dumps(x))

Output:

{"ID": 1111, "Group": "Admin"}

Have a look at the following snippet given below to compare and contrast how complex and messy the syntax becomes when we try to print the same string using {{}} in our program.

group = "Admin"
id = 1111
print('{{"ID": {}, "Group": {}}}'.format(id,group))

Output:

{"ID": 1111, "Group": Admin}

Method 4: Using Template Strings

Template strings are used to provide string substitutions. If you want to avoid extra curly braces and % based substitutions then you can use the Template class of the string module.

★ The substitute() method performs template substitution a returns a new string.

Disclaimer: This might be a little confusing and prone to several exceptions if not properly used which is why I personally do not recommend you to use this procedure unless absolutely necessary.

Let us have a look at the following program to understand the usage of Template strings:

from string import Template
x = Template("$open Serial No: $close")
x = x.substitute(open='{',close='}')
print('{} {}'.format(x,1))

Output:

{ Serial No: } 1

EXERCISE

Now let’s get our hands dirty and practice some coding. Can you guess the output of the following snippet?

Note: Make sure you follow the comments in the given snippet which will unlock an important concept for you!

greet = "HELLO FINXTER"
name = input("Enter Your Name: ")
age = input("Enter Your Age:")
print("\n")
# to resolve an expression in the brackets instead of using literal text use three sets of curly braces
print(f"{{{greet.lower()}}} {name}")
print('{{You are {} years old!}}'.format(age))

Conclusion

In this article, we discussed various methods to format a string that contains curly braces in Python. Frankly speaking, the double curly braces is the simplest solution while using the JSON Library is the most efficient method while dealing with complex JSON data. However, you are always free to use any method that suits your requirements and the best way of getting hold of all these techniques is to practice them. So without further delay, please try them in your system, and please feel free to drop queries.

Please subscribe and stay tuned for more interesting articles!

Where to Go From Here?

Enough theory, let’s get some practice!

To become successful in coding, you need to get out there and solve real problems for real people. That’s how you can become a six-figure earner easily. And that’s how you polish the skills you really need in practice. After all, what’s the use of learning theory that nobody ever needs?

Practice projects is how you sharpen your saw in coding!

Do you want to become a code master by focusing on practical code projects that actually earn you money and solve problems for people?

Then become a Python freelance developer! It’s the best way of approaching the task of improving your Python skills—even if you are a complete beginner.

Join my free webinar “How to Build Your High-Income Skill Python” and watch how I grew my coding business online and how you can, too—from the comfort of your own home.

Join the free webinar now!

The post How To Format A String That Contains Curly Braces In Python? first appeared on Finxter.

This short article is based on the ultimate guide to freelance developing on the Finxter blog.

You’ll first learn about the definition of freelancing. Then, I’ll show you how you can evaluate whether the freelance developing niche is attractive for you and whether you can expect it to grow over time. So, let’s get started, shall we?

Definition

Freelancing is the act of delivering a service to another business or another customer in exchange for a defined rate.

If you travel back in time—say, ten years—freelancing would be the act of delivering your services to another business: a B2B (business-to-business) transaction.

But, since the appearance of freelancing platforms such as Upwork or Fiverr, it more and more became a B2C (business-to-customer) transaction. There are plenty of people, often employees, who need your services to become more and more productive.

In essence, you’re solving problems for other people. These people can be businesses, private persons, or employees. These people hire you to solve a problem for them. This makes perfect sense: in our world, everyone is a business owner.

As a person, employee, or freelancer, you are a one-person business that gets hired by organizations and other businesses.

As an employee, you are already a freelancer—have a look at the definition again. You sell your services to another party. You get paid by the hour. If you have experience as an employee, you have experience as a freelancer, too, because being an employee is nothing but a special case of being a freelancer.

But there are many more forms of freelancing. As an employee, you’re in a contract between your employer and yourself that ranges for many months. As a freelancer, you can also have these types of contracts: You can agree to contracts that range many years—in fact, businesses hire freelancers often on a long-term basis. If it makes economic sense to hire you once, why shouldn’t it make sense to hire you on a regular basis? But you can also have much smaller contracts that range only for a few hours.

Freelancing comes with all kinds of advantages and disadvantages. But as the term freelancing is so broadly defined, you cannot really generalize those: no advantage and no disadvantage will apply to any type of freelancing gig. Well, as a freelancer, you can aim for the best of both worlds: income security and higher income—if you design your freelancing business in an intelligent way.

Let’s have a deeper look into the freelance developer niche—is it attractive?

About the Freelance Developing Niche

Make no mistake: niche selection is critical.

Many people will tell you that you can select any niche. But this is only partially true.

Sure, if you join the top 10% of people in any niche, you’ll earn a lot of money and you’ll succeed in your profession.

But if you select the right niche, you can earn 10x or even 100x as a person in the top 10%. An example would be the niche “journalism” vs “machine learning engineer“.

• As a top journalist, you can expect to earn $50,000-$100,000 per year. (source)
• As a top machine learning engineer, you can expect to earn $200,000-$1,000,000 per year. (source)

That’s 4x to 10x difference in earnings of the top guys and gals! Niche selection is crucial.

Python Employee vs Freelancer

So, you may ask: should you go into the freelance developing niche—for instance, Python freelancing—or should you go into the pure Python development niche and become an employee?

I’ve recently read a book from the great Richard Koch: The Star Principle. He’s the author of The 80/20 Principle as well and he’s worth hundreds of millions of dollars. How has he done it?

He invests all his money in so-called “star companies”. And he has worked all his life in the same “star companies”. These companies generate lots of cash and everyone who’s involved benefits from their cash-generating ability.

A star business is an industry leader in a high-growth industry. This concept was developed by the Boston Consulting Group many decades ago—but it still applies to today’s businesses. Have a look at the matrix taken from BCG:

You want to invest your time and money only into businesses that are in high-growth markets and that have a high market share. An example is Google as the leader in the search engine market when the search engine market was still growing by more than 10% per year. Today, Google would be a “Cash Cow” according to the model—still attractive but not necessarily a star anymore.

The combination of being an industry leader and being in a high-growth market is very powerful.

• As an industry leader, you have higher profit margins and more cash to reinvest than any other player in the market. This allows you to keep your growth rate over each other player in the market. Plus, you enjoy strong network effects (“the rich get richer”)—everyone knows you’re the leader so customers will come to you which reinforces your position as the leader.
• As a company in a high-growth market, you will grow significantly even if you only maintain your market share.

If you can participate in a company that is the leader in a high-growth niche, you can expect significant benefits (if you don’t overpay as an investor).

So, how does it apply to the freelance developer niche?

The freelancing niche is growing double digits every year. Both companies Upwork and Fiverr (the industry leaders) grow more than 10% per year for many years.

These companies are out to disrupt the organization of the world’s talents. And if they keep growing, they’ll accomplish it!

As a developer, as a coder, you’re in an industry that grows 5% per year based on my estimation. It’s an attractive industry but it’s not a “star industry” anymore. Coding is still important and it will grow in importance over time. But it is not a high-growth niche anymore.

As a freelance developer though, you’re both in the freelancing and in the developer niche. Both grow significantly and their growth compounds. So, being a freelance developer is an extremely attractive niche.

If you combine it with Python which is the fastest-growing major programming language, you obtain a combination that has a high potential to transform your life.

If you want to participate in this disruptive trend, you should consider becoming a Python freelancer. Check out my Python freelancer course to get this going FAST!

Leaving the Rat Race

Do you want to develop the skills of a well-rounded Python professional—while getting paid in the process? Become a Python freelancer and order your book Leaving the Rat Race with Python on Amazon (Kindle/Print)!

The post Freelance Developing Niche first appeared on Finxter.