[Tut] Python List pop()

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Python List pop()

This tutorial shows you everything you need to know to help you master the essential

Code:

pop()

method of the most fundamental container data type in the Python programming language.

Definition and Usage:

The

Code:

list.pop()

method removes and returns the last element from an existing

Code:

list

. The

Code:

list.pop(index)

method with the optional argument

Code:

index

removes and returns the element at the position

Code:

index

.

Here’s a short example:

Code:

>>> lst = [1, 2, 3] >>> lst.pop() 3 >>> lst [1, 2]

In the first line of the example, you create the list

Code:

lst

. You then remove and return the final element 3 from the list. The result is the list with only two elements

Code:

[1, 2]

.

Code Puzzle — Try It Yourself:

Now you know the basics. Let’s deepen your understanding with a short code puzzle—can you solve it?

https://repl.it/repls/UsedSquareExperiments?lite=true

You can also solve this puzzle and track your Python skills on our interactive Finxter app.

Syntax:

You can call this method on each list object in Python. Here’s the syntax:

Code:

list.pop(index=-1)

Arguments:

Argument |
Description

Code:

index

|
Optional argument. You can define the index of the element to be removed and returned. The default argument leads to the removal of the last list element with index -1.

Return value:

The method

Code:

list.pop()

has return value

Code:

Object

. It removes the respective element from the list (default: the last element) and returns it directly to the caller.

Video:



Python List pop() By Index

You can use the

Code:

list.pop(index)

method to with the optional index argument to remove and return the element at position

Code:

index

from the list.

Here’s an example:

Code:

>>> customers = ['Alice', 'Bob', 'Ann', 'Frank'] >>> customers.pop(2) 'Ann' >>> customers ['Alice', 'Bob', 'Frank'] >>> customers.pop(0) 'Alice' >>> customers ['Bob', 'Frank']

After creating the list with four elements, you first remove and return the second element

Code:

'Ann'

. Then, you remove and return the first element

Code:

'Alice'

. The resulting list has only two elements left.

Python List pop() First / Front / Left / Head

The

Code:

list.pop(index)

method to with the optional index argument to remove and return the element at position

Code:

index

from the list. So if you want to remove the first element from the list, simply set

Code:

index=0

by calling

Code:

list.pop(0)

. This will pop the first element from the list.

Here’s an example:

Code:

>>> primes = [1, 2, 3, 5, 7, 11] >>> primes.pop(0) 1 >>> primes [2, 3, 5, 7, 11]

The

Code:

pop(0)

method removes the first element 1 from the list of prime numbers given in the example.

Python List pop() By Value

In the previous two examples, you’ve seen how to pop elements by index. But can you also pop by value?

Yes, you can by using the

Code:

list.index(value)

method which gives you the index of the element value in the list. Now, you can use the

Code:

list.pop(index)

method on this index to remove the value from the list and get the result as a return value.

Here’s an example where you want to pop the element 7 from the list and store the result in the variable

Code:

some_prime

.

Code:

>>> primes = [1, 2, 3, 5, 7, 11] >>> some_prime = primes.pop(primes.index(7)) >>> some_prime 7

If you’re not interested in the return value but you only want to remove the first occurrence of the value

Code:

x

in the

Code:

list

, use the

Code:

list.remove(x)

method.

Related Article:

• Python List remove()
  

Python List pop() Multiple Elements

Python List pop() First n Elements

Python List pop() Last n Elements

Python List pop() Time Complexity … First and Last and General cases

Python List pop() vs remove()

Python List Pop and Push (Stack)

Python List pop() Without Remove

Python List pop() While Iterating

Python List pop() If Not Empty

Python List pop() Slice

Alternatives Ways to Remove Elements From a List

There are some alternative ways to remove elements from the list. See the overview table:

Method |
Description

Code:

lst.remove(x)

|
Remove an element from the list (by value)

Code:

lst.pop()

|
Remove an element from the list (by index) and return the element

Code:

lst.clear()

|
Remove all elements from the list

Code:

del lst[3]

|
Remove one or more elements from the list (by index or slice)

List comprehension |
Remove all elements that meet a certain condition

Next, you’ll dive into each of those methods to gain some deep understanding.

remove() — Remove An Element by Value

To remove an element from the list, use the

Code:

list.remove(element)

method you’ve already seen previously:

Code:

>>> lst = ["Alice", 3, "alice", "Ann", 42] >>> lst.remove("Ann") >>> lst ['Alice', 3, 'alice', 42]

Try it yourself:

https://repl.it/repls/CurlyIdioticChief?lite=true

The method goes from left to right and removes the first occurrence of the element that’s equal to the one to be removed.

Removed Element Does Not Exist

If you’re trying to remove element x from the list but x does not exist in the list, Python throws a Value error:

Code:

>>> lst = ['Alice', 'Bob', 'Ann'] >>> lst.remove('Frank') Traceback (most recent call last): File "<pyshell#19>", line 1, in <module> lst.remove('Frank') ValueError: list.remove(x): x not in list

pop() — Remove An Element by Index

https://repl.it/repls/CurlyIdioticChief?lite=true

Per default, the

Code:

pop()

method removes the last element from the list and returns the element.

Code:

>>> lst = ['Alice', 'Bob', 'Ann'] >>> lst.pop() 'Ann' >>> lst ['Alice', 'Bob']

But you can also define the optional index argument. In this case, you’ll remove the element at the given index—a little known Python secret!

Code:

>>> lst = ['Alice', 'Bob', 'Ann'] >>> lst.pop(1) 'Bob' >>> lst ['Alice', 'Ann']

clear() — Remove All Elements

https://repl.it/repls/TightWiseTechnician?lite=true

The

Code:

clear()

method simply removes all elements from a given list object.

Code:

>>> lst = ['Alice', 'Bob', 'Ann'] >>> lst.clear() >>> lst []

del — Remove Elements by Index or Slice

https://repl.it/repls/ClientsideForsaken...?lite=true

This trick is also relatively unknown among Python beginners:

• Use
  Code:

  del lst[index]
  to remove the element at index.
  
  
• Use
  Code:

  del lst[start:stop]
  to remove all elements in the slice.
  

Code:

>>> lst = list(range(10)) >>> lst [0, 1, 2, 3, 4, 5, 6, 7, 8, 9] >>> del lst[5] >>> lst [0, 1, 2, 3, 4, 6, 7, 8, 9] >>> del lst[:4] >>> lst [4, 6, 7, 8, 9]

Related blog articles:

• Check out my full slicing tutorial that makes you a master slicer in 15 minutes or so!
  

List Comprehension — Remove Elements Conditionally

https://repl.it/repls/FabulousMadEquation?lite=true

Okay, this is kind of cheating because this method does not really remove elements from a list object. It merely creates a new list with some elements that meet your condition.

List comprehension is a compact way of creating lists. The simple formula is [ expression + context ].

• Expression: What to do with each list element?
  
  
• Context: What list elements to select? It consists of an arbitrary number of for and if statements.
  

The example

Code:

[x for x in range(3)]

creates the list

Code:

[0, 1, 2]

.

You can also define a condition such as all odd values

Code:

x%2==1

in the context part by using an if condition. This leads us to a way to remove all elements that do not meet a certain condition in a given list.

Code:

>>> lst = list(range(10)) >>> lst_new = [x for x in lst if x%2] >>> lst_new [1, 3, 5, 7, 9]

While you iterate over the whole list

Code:

lst

, the condition

Code:

x%2

requires that the elements are odd.

Related blog articles:

• Check out my full list comprehension tutorial for maximal learning!
  

Python List pop() Thread Safe

Do you have a multiple threads that access your list at the same time? Then you need to be sure that the list operations (such as

Code:

pop()

) are actually thread safe.

In other words: can you call the

Code:

pop()

operation in two threads on the same list at the same time? (And can you be sure that the result is meaningful?)

The answer is yes (if you use the cPythonimplementation). The reason is Python’s global interpreter lock that ensures that a thread that’s currently working on it’s code will first finish its current basic Python operation as defined by the cPython implementation. Only if it terminates with this operation will the next thread be able to access the computational resource. This is ensured with a sophisticated locking scheme by the cPython implementation.

The only thing you need to know is that each basic operation in the cPython implementation is atomic. It’s executed wholly and at once before any other thread has the chance to run on the same virtual engine. Therefore, there are no race conditions. An example for such a race condition would be the following: the first thread reads a value from the list, the second threads overwrites the value, and the first thread overwrites the value again invalidating the second thread’s operation.

All cPython operations are thread-safe. But if you combine those operations into higher-level functions, those are not generally thread safe as they consist of many (possibly interleaving) operations.

Where to Go From Here?

The

Code:

list.remove(element)

method removes the first occurrence of

Code:

element

from the

Code:

list

.

You’ve learned the ins and outs of this important Python list method.

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