12-05-2022, 01:21 PM
Python | Split String by Number
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Summary: To split a string by a number, use the regex method using the “” pattern.
[b]Minimal Example[/b]
[b]Problem Formulation[/b]
Problem: Given a string containing different characters. How will you split the string whenever a number appears?
Method 1: re.split()
The method matches all occurrences of the in the and divides the string along the matches resulting in a list of strings between the matches. For example, results in the list of strings .
Code:
Explanation: The special character matches any digit between 0 and 9. By using the maximal number of digits as a delimiter, you split along the digit-word boundary.
Method 2: re.findall()
The method scans from left to right, searching for all non-overlapping matches of the . It returns a list of strings in the matching order when scanning the string from left to right.
Code:
Explanation: TheD special character matches all characters except any digit between 0 and 9. Thus, you are essentially finding all character groups that appear before the occurrence of a digit.
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Method 3: itertools.groupby()
Code:
Explanation:
Method 4: Replace Using a for Loop
Approach: Use a for loop to iterate through the characters of the given string. Check if a character is a digit or not. As soon as a digit is found, replace that character/digit with a delimiter string ( we have used a comma here) with the help of the replace() method. This basically means that you are placing a particular character in the string whenever a number appears. Once all the digits are replaced by the separator string, split the string by passing the separator string as a delimiter to the split method.
Code:
[b]Conclusion[/b]
Phew! We have successfully solved the given problem and managed to do so using four different ways. I hope you found this article helpful and it answered your queries. Please subscribe and stay tuned for more solutions and tutorials.
Happy coding!![[Image: 1f642.png]](https://s.w.org/images/core/emoji/14.0.0/72x72/1f642.png)
Related Read:How to Split a String Between Numbers and Letters?
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Summary: To split a string by a number, use the regex Code:
splitCode:
\d[b]Minimal Example[/b]
Code:
my_string = "#@1abc3$!*5xyz" # Method 1
import re res = re.split('\d+', my_string)
print(res) # Method 2
import re res = re.findall('\D+', my_string)
print(res) # Method 3
from itertools import groupby li = [''.join(g) for _, g in groupby(my_string, str.isdigit)]
res = [x for x in li if x.isdigit() == False]
print(res) # Method 4
res = []
for i in my_string: if i.isdigit() == True: my_string = my_string.replace(i, ",")
print(my_string.split(",")) # Outputs:
# ['#@', 'abc', '$!*', 'xyz'][b]Problem Formulation[/b]
Problem: Given a string containing different characters. How will you split the string whenever a number appears?Method 1: re.split()
The
Code:
re.split(pattern, string)Code:
patternCode:
stringCode:
re.split('a', 'bbabbbab')Code:
['bb', 'bbb', 'b']Code:
Code:
import re
my_string = "#@1abc3$!*5xyz"
res = re.split('\d+', my_string)
print(res) # ['#@', 'abc', '$!*', 'xyz']Explanation: The
Code:
\dMethod 2: re.findall()
The
Code:
re.findall(pattern, string)Code:
stringCode:
patternCode:
Code:
import re
my_string = "#@1abc3$!*5xyz"
res = re.findall('\D+', my_string)
print(res) # ['#@', 'abc', '$!*', 'xyz']Explanation: The
Code:
\Do you want to master the regex superpower? Check out my new book The Smartest Way to Learn Regular Expressions in Python with the innovative 3-step approach for active learning: (1) study a book chapter, (2) solve a code puzzle, and (3) watch an educational chapter video.
Method 3: itertools.groupby()
Code:
Code:
from itertools import groupby
my_string = "#@1abc3$!*5xyz"
li = [''.join(g) for _, g in groupby(my_string, str.isdigit)]
res = [x for x in li if x.isdigit() == False]
print(res) # ['#@', 'abc', '$!*', 'xyz']Explanation:
- The function creates an iterator that returns tuplesCode:
itertools.groupby(iterable, key=None)grouped by each value ofCode:(key, group-iterator). We use theCode:keyfunction as key function.Code:str.isdigit()
- The function returnsCode:
str.isdigit()if the string consists only of numeric characters. Thus, you will have a list created by using numbers as separators. Note that this list will also contain the numbers as items within it.Code:True
- In order to eliminate the numbers, use another list comprehension that checks if an element in the list returned previously is a digit or not with the help of the method. If it is a digit, the item will be discarded. Otherwise it will be stored in the list.Code:
isdigit
Method 4: Replace Using a for Loop
Approach: Use a for loop to iterate through the characters of the given string. Check if a character is a digit or not. As soon as a digit is found, replace that character/digit with a delimiter string ( we have used a comma here) with the help of the replace() method. This basically means that you are placing a particular character in the string whenever a number appears. Once all the digits are replaced by the separator string, split the string by passing the separator string as a delimiter to the split method.
Code:
Code:
my_string = "#@1abc3$!*5xyz"
res = []
for i in my_string: if i.isdigit(): my_string = my_string.replace(i, ",")
print(my_string.split(",")) # ['#@', 'abc', '$!*', 'xyz']Phew! We have successfully solved the given problem and managed to do so using four different ways. I hope you found this article helpful and it answered your queries. Please subscribe and stay tuned for more solutions and tutorials.
Happy coding!
![[Image: 1f642.png]](https://s.w.org/images/core/emoji/14.0.0/72x72/1f642.png)
Related Read:How to Split a String Between Numbers and Letters?

