[Tut] [Resolve] IndexError: List Assignment Index Out of Range

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[Resolve] IndexError: List Assignment Index Out of Range



When does the

Code:

IndexError: list assignment index out of range

appear?

Python throws an

Code:

IndexError

if you try to assign a value to a list index that doesn’t exist, yet. For example, if you execute the expression

Code:

list[1] = 10

on an empty

Code:

list

, Python throws the

Code:

IndexError

. Simply resolve it by adding elements to your list until the index actually exists.



Here’s the minimal example that throws the IndexError:

Code:

lst = [] lst[1] = 10

If you run this code, you’ll see that Python throws an

Code:

IndexError

:

Code:

Traceback (most recent call last): File "C:\Users\xcent\Desktop\code.py", line 2, in <module> lst[1] = 10 IndexError: list assignment index out of range

You can resolve it by adding two “dummy” elements to the list so that the index 1 actually exists in the list:

Code:

lst = [None, None] lst[1] = 10 print(lst)

Now, Python will print the expected output:

Code:

[None, 10]

Try to fix the

Code:

IndexError

in the following interactive code shell:

https://repl.it/@finxter/RemarkablePunge...?lite=true

Exercise: Can you fix this code?

So what are some other occurrences of the IndexError?

IndexError in For Loop

Frequently, the

Code:

IndexError

happens if you use a

Code:

for

loop to modify some list elements like here:

Code:

# WRONG CODE: lst = [] for i in range(10): lst[i] = i print(lst)

Again, the result is an

Code:

IndexError

:

Code:

Traceback (most recent call last): File "C:\Users\xcent\Desktop\code.py", line 4, in <module> lst[i] = i IndexError: list assignment index out of range

You modify a list element at index

Code:

i

that doesn’t exist in the list. Instead, create the list using the

Code:

list(range(10))

list constructor.

Code:

# CORRECT CODE: lst = list(range(10)) print(lst) # [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Where to Go From Here?

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