{"id":130239,"date":"2022-12-03T18:05:33","date_gmt":"2022-12-03T18:05:33","guid":{"rendered":"https:\/\/blog.finxter.com\/?p=950806"},"modified":"2022-12-03T18:05:33","modified_gmt":"2022-12-03T18:05:33","slug":"python-split-string-by-number","status":"publish","type":"post","link":"https:\/\/sickgaming.net\/blog\/2022\/12\/03\/python-split-string-by-number\/","title":{"rendered":"Python | Split String by Number"},"content":{"rendered":"\n
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\"\u2728\"Summary:<\/strong> To split a string by a number, use the regex split<\/code> method using the “\\d<\/code>” pattern. <\/p>\n

Minimal Example<\/strong><\/h3>\n
my_string = \"#@1abc3$!*5xyz\" # Method 1\nimport re res = re.split('\\d+', my_string)\nprint(res) # Method 2\nimport re res = re.findall('\\D+', my_string)\nprint(res) # Method 3\nfrom itertools import groupby li = [''.join(g) for _, g in groupby(my_string, str.isdigit)]\nres = [x for x in li if x.isdigit() == False]\nprint(res) # Method 4\nres = []\nfor i in my_string: if i.isdigit() == True: my_string = my_string.replace(i, \",\")\nprint(my_string.split(\",\")) # Outputs:\n# ['#@', 'abc', '$!*', 'xyz']<\/pre>\n
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Problem Formulation<\/strong><\/h2>\n
\"\ud83d\udcdc\"Problem:<\/strong> Given a string containing different characters. How will you split the string whenever a number appears?<\/p>\n
Method 1: re.split()<\/h2>\n
The\u00a0re.split(pattern, string)<\/a><\/code>\u00a0method matches all occurrences of the\u00a0pattern<\/code>\u00a0in the\u00a0string<\/code>\u00a0and divides the string along the matches resulting in a list of strings\u00a0between\u00a0<\/em>the matches. For example,\u00a0re.split('a', 'bbabbbab')<\/code>\u00a0results in the list of strings\u00a0['bb', 'bbb', 'b']<\/code>.<\/p>\n
Code:<\/strong><\/p>\n
import re\nmy_string = \"#@1abc3$!*5xyz\"\nres = re.split('\\d+', my_string)\nprint(res) # ['#@', 'abc', '$!*', 'xyz']<\/pre>\n
Explanation: <\/strong>The\u00a0\\d<\/code>\u00a0special character<\/a>\u00a0matches any digit between 0 and 9. By using the maximal number of digits as a delimiter, you split along the digit-word boundary.\u00a0<\/p>\n
Method 2: re.findall()<\/h2>\n
The\u00a0re.findall(pattern, string)<\/a><\/code>\u00a0method scans\u00a0string<\/code>\u00a0from\u00a0left to right<\/strong>, searching for all\u00a0non-overlapping matches<\/strong>\u00a0of the\u00a0pattern<\/code>. It returns a\u00a0list of strings<\/strong>\u00a0in the matching order when scanning the string from left to right.<\/p>\n
Code:<\/strong><\/p>\n
import re\nmy_string = \"#@1abc3$!*5xyz\"\nres = re.findall('\\D+', my_string)\nprint(res) # ['#@', 'abc', '$!*', 'xyz']<\/pre>\n
Explanation: <\/strong>The\u00a0\\<\/code>D\u00a0special character<\/a>\u00a0matches all characters except any digit between 0 and 9. Thus, you are essentially finding all character groups that appear before the occurrence of a digit. <\/p>\n
Do you want to master the regex superpower?<\/em><\/strong> Check out my new book The Smartest Way to Learn Regular Expressions in Python<\/a><\/strong><\/em> with the innovative 3-step approach for active learning: (1) study a book chapter, (2) solve a code puzzle, and (3) watch an educational chapter video. <\/p>\n
Method 3: itertools.groupby()<\/h2>\n
Code:<\/strong><\/p>\n
from itertools import groupby\nmy_string = \"#@1abc3$!*5xyz\"\nli = [''.join(g) for _, g in groupby(my_string, str.isdigit)]\nres = [x for x in li if x.isdigit() == False]\nprint(res) # ['#@', 'abc', '$!*', 'xyz']<\/pre>\n
Explanation:<\/strong> <\/p>\n