{"id":115771,"date":"2020-07-23T06:56:49","date_gmt":"2020-07-23T06:56:49","guid":{"rendered":"https:\/\/blog.finxter.com\/?p=11312"},"modified":"2020-07-23T06:56:49","modified_gmt":"2020-07-23T06:56:49","slug":"python-one-line-for-loop-lambda","status":"publish","type":"post","link":"https:\/\/sickgaming.net\/blog\/2020\/07\/23\/python-one-line-for-loop-lambda\/","title":{"rendered":"Python One Line For Loop Lambda"},"content":{"rendered":"

Problem<\/strong>: Given a collection. You want to create a new list based on all values in this collection. The code should run in a single line of code. How do you accomplish this? Do you need a lambda function<\/a>?<\/p>\n

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\"Python<\/figure>\n<\/div>\n

Example<\/strong>: Given an array a = [1, 2, 3, 4]<\/code>. You need to create a second array b<\/code> with all values of a<\/code>—while adding +1<\/code> to each value. Here’s your multi-liner:<\/p>\n

a = [1, 2, 3, 4]\nb = []\nfor x in a: b.append(x+1)\nprint(b)\n# [2, 3, 4, 5]<\/pre>\n
How do you accomplish this in a single line of code?<\/p>\n
Answer<\/strong>: No, you don’t need a lambda function. What you’re looking for is a feature called list comprehension<\/a>. Here’s the one-liner expression that accomplishes this without the lambda function:<\/p>\n
b = [x+1 for x in a]\nprint(b)\n# [2, 3, 4, 5]<\/pre>\n
You can try this example yourself in our interactive code shell:<\/p>\n